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Jharkhand JSSC Jharkhand JSSC Para Teacher Recruitment 2026 Apply Online for 6101 Post

Post Date: 04 Oct 2026Updated: 04 Oct 2026
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Brief Description:Jharkhand JSSC Para Teacher Online Form 2026 for 6101 Post | Check Recruitment Notification | Age Limit, Eligibility, How to Apply at Sarkari Result
Important Dates (महत्वपूर्ण तिथियाँ)
Application Begin :29/09/2026
Last Date for Apply Online :18/10/2026
Pay Exam Fee Last Date :18/10/2026
Photo / Signature Upload Last Date :22/10/2026
Correction Date :23-24 October 2026
JSSC Para Teacher Exam Date :As per Schedule
Admit Card Available :Before Exam
Application Fee (आवेदन शुल्क)
General / OBC / Other State :₹100/-
SC / ST :₹50/-
Payment Mode: Pay the Exam Fee Through Online / Offline Fee Mode Only
Age Limit & Eligibility (आयु सीमा और योग्यता)
Minimum Age:18 Years
Maximum Age:35 Years
Age Calculate as on:01/08/2026

• Age Relaxation Extra as per Recruitment Rules.

How to Fill Online Application Form (आवेदन कैसे करें)

  • 1.Candidate can apply online by visiting the official portal before the last date.
  • 2.Read the full notification carefully before filling the application form.
  • 3.Check and collect all required documents: Eligibility proof, ID proof, Address details, and Basic details.
  • 4.Keep scanned copies ready for Photo, Signature, ID Proof, etc.
  • 5.Before submitting the form, carefully preview all columns and verify details.
  • 6.Take a printout of the finalized submitted application form for future reference.

Vacancy Details (पदों का विवरण)

Post Wise Vacancy Breakdown & Eligibility Criteria

कुल पद: 12202 Posts
Post Name (पद का नाम)Total Post (कुल पद)Eligibility Criteria (योग्यता विवरण)
Intermediate Trained Assistant Acharya (Class 1-5)
1,909
  • 10+2 (Intermediate) with required marks and 2 Year D.El.Ed / Diploma in Elementary Education / B.El.Ed / Diploma in Special Education / Graduation + D.El.Ed. Must have JTET / CTET (Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Language
1,868
  • Bachelor’s Degree in the relevant Language subject with B.Ed / B.A. B.Ed / B.Sc. B.Ed / B.Ed (Special Education) / Integrated B.Ed-M.Ed. Must have JTET / CTET (Upper Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Social Science
660
  • Bachelor’s Degree in Arts / Humanities / Social Science / Commerce / Management with B.Ed or equivalent qualification. Must have JTET / CTET (Upper Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Mathematics & Science
1,664
  • Bachelor’s Degree in Mathematics / Science with B.Ed / B.Sc. B.Ed / B.A. B.Ed / Integrated B.Ed or equivalent qualification. Must have JTET / CTET (Upper Primary Level) qualification.
Intermediate Trained Assistant Acharya (Class 1-5)
1,909
  • 10+2 (Intermediate) with required marks and 2 Year D.El.Ed / Diploma in Elementary Education / B.El.Ed / Diploma in Special Education / Graduation + D.El.Ed. Must have JTET / CTET (Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Language
1,868
  • Bachelor’s Degree in the relevant Language subject with B.Ed / B.A. B.Ed / B.Sc. B.Ed / B.Ed (Special Education) / Integrated B.Ed-M.Ed. Must have JTET / CTET (Upper Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Social Science
660
  • Bachelor’s Degree in Arts / Humanities / Social Science / Commerce / Management with B.Ed or equivalent qualification. Must have JTET / CTET (Upper Primary Level) qualification.
Graduate Trained Assistant Acharya (Class 6-8) – Mathematics & Science
1,664
  • Bachelor’s Degree in Mathematics / Science with B.Ed / B.Sc. B.Ed / B.A. B.Ed / Integrated B.Ed or equivalent qualification. Must have JTET / CTET (Upper Primary Level) qualification.
* For category-wise reservation & age relaxation, check official notification.ResultForIndia.com
Important Useful Links (उपयोगी लिंक)
Check Result / Cutoff MarksClick Here (यहाँ क्लिक करें)
Apply OnlineClick Here (यहाँ क्लिक करें)
Download Official NotificationClick Here (यहाँ क्लिक करें)
Official WebsiteClick Here (यहाँ क्लिक करें)
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Frequently Asked Questions (Jharkhand JSSC Jharkhand JSSC Para Teacher Recruitment 2026 Apply Online for 6101 Post)

Q1: What is the last date to apply for Jharkhand JSSC Jharkhand JSSC Para Teacher Recruitment 2026 Apply Online for 6101 Post?

Ans: The last date to submit online application forms is 18/10/2026.

Q2: How many vacancies are released for Jharkhand JSSC Jharkhand JSSC Para Teacher Recruitment 2026 Apply Online for 6101 Post?

Ans: Total vacancies announced: 12202 Posts.

Q4: Where to find official link for Jharkhand JSSC Jharkhand JSSC Para Teacher Recruitment 2026 Apply Online for 6101 Post?

Ans: Direct links for Apply Online, Download Notification, and Official Website are provided above in the Useful Important Links table on Result For India.

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